Selasa, 07 Juli 2020

Find Factors and Multiples of Whole Numbers

Examples and questions on how to find factors and multiples of whole numbers , with detailed solutions and explanations, for grade 6 students are presented.
Factors.
Division and multiplication are related operations.
The division 6 ÷ 3 = 2 (with remainder equal to 0) may be written 
as the multiplication: 6 = 2 × 3
The division 15 ÷ 3 = 5 (with remainder equal to 0) may be written 
as the multiplication: 15 = 5 × 3
The multiplication: 10 = 2 × 5 may be written as the division: 10 ÷ 5 = 2 
(with remainder equal to 0)
The multiplication: 18 = 6 × 3 may be written as the division: 18 ÷ 3 = 6 
(with remainder equal to 0)
To factor a whole number is to write it as a product of two or more whole numbers.
Examples

1) 6 = 1 × 6 ; 6 = 2 × 3     1, 2, 3 and 6 are called factors of 6.
2) 12 = 12 ×1 = 3 × 4 = 6 ×2     1, 2, 3, 4, 6 and 12 are called factors of 12.
3) 20 = 1 × 20 = 2 × 10 = 2 × 2 × 5 = 4 × 5     1, 2, 3, 4, 5, 10 and 20
are called factors of 20.
How to find all factors of a whole number?.
Examples
Find all factors of 30
Divide 30 by all numbers starting from 1 and select the division
that gives a remainder
equal to 0 then write the factors.
30 ÷ 1 = 30 remainder 0 or 30 = 30 × 1. Hence 1 and 30 are factors
30 ÷ 2 = 15 remainder 0 or 30 = 15 × 2 . Hence both 2 and 15 are factors
30 ÷ 3 = 10 remainder 0 or 30 = 10 × 3 . Hence both 3 and 10 are factors
30 ÷ 4 = 7 remainder 2 , 4 is not a factor
30 ÷ 5 = 6 remainder 0 or 30 = 6 × 5 . Hence both 5 and 6 area factors.
We stop here because all factors greater that 5 have already been found.
The factors of 30 are: 1, 2, 3, 5, 6, 10, 15, 30
Multiples
Take a whole number and multiply it by 1, 2, 3, 4, ... to obtain the multiples as follows:
5 × 1 = 5
5 × 2 = 10
5 × 3 = 15
5 × 4 = 20

The results of the multiplication of 5 by 1, 2, 3, 4, ... which are 5, 10, 15, 20, ..
are called the multiples of 5.

    Answer the Following Questions

    1.  Which of the following statements is TRUE and which is FALSE? Explain your answer.
      1. The division of 4 by 2 is equal to 2 with remainder not equal to zero.
      2. 3 is a factor of 9.
      3. 5 and 3 are factors of 15
      4. 3 is a factor of 7.
      5. The division of 10 by 10 gives a remainder equal to 0.
      6. 16 is a factor of 16.
      7. 1 is a factor to all whole numbers.
      8. Any whole number greater than 1 has at least two factors
    2.  
    3. Find all factors to the whole numbers below.
      1. 2
      2. 6
      3. 10
      4. 24
    4. Which of the following numbers is a factor of 120?
      1. 2
      2. 5
      3. 10
      4. 11
      5. 20
      6. 30
      7. 50
    5. Find and order from smallest to largest all factors of 12 and all factors of 24. Find all factors that are common (the same) to 12 and 24.
    6. Find the first 5 multiples of each of the numbers below.
      1. 2
      2. 11
      3. 25
    7. Find the first 5 multiples of 6 and 8. Find a multiple that is common (the same) to both 6 and 8.

    Solutions to the Above Problems

    1. Solution
      1. The division of 4 by 2 is equal to 2 with remainder not equal to zero.
        FALSE 4 ÷ 2 = 2 with remainder 0
      2. 3 is a factor of 9.
        TRUE 9 = 3 × 3
      3. 5 and 3 are factors of 15
        TRUE 15 = 5 × 3
      4. 3 is a factor of 7.
        FALSE There is no whole number N such that 7 = 3 × N
      5. The division of 10 by 10 gives a remainder equal to 0.
        TRUE 10 ÷ 10 = 1 with remainder equal to 0.
      6. 16 is a factor of 16.
        TRUE 16 = 16 × 1
      7. 1 is a factor to all whole numbers.
        TRUE N = N × 1
      8. Any whole number greater than 1 has at least two factors.
        TRUE N = N × 1 , at least two factors 1 and N (itself)
    2. Solution
      1. 2
        2 ÷ 1 = 2 with remainder 0 or 2 = 2 × 1 . Hence the factors of 2 are 1 and 2.
      2. 6
        6 ÷ 1 = 6 with remainder 0 or 6 = 6 × 1. Two factors 1 and 6.
        6 ÷ 2 = 3 with remainder 0 or 6 = 3 × 2. Two factors 2 and 3.
        All factors greater than 2 already found, we stop the division process and write the list of factors of 6 are 1, 2, 3 and 6.
      3. 10
        10 ÷ 1 = 10 with remainder 0 or 10 = 10 × 1. Two factors 1 and 10.
        10 ÷ 2 = 5 with remainder 0 or 10 = 5 × 2. Two factors 2 and 5.
        10 ÷ 3 = 3 with remainder 1; 3 is not a factor of 10.
        10 ÷ 4 = 2 with remainder 2; 4 is not a factor 10.
        All factors greater that 4 already found, we stop the division process and write the list of factors 10 are 1, 2, 5 and 10.
      4. 24
        24 ÷ 1 = 24 with remainder 0 or 24 = 24 × 1. Two factors 1 and 24.
        24 ÷ 2 = 12 with remainder 0 or 24 = 12 × 2. Two factors 2 and 12.24 ÷ 3 = 8 with remainder 0 ; or 24 = 8 × 3. Two factors 3 and 8.
        24 ÷ 4 = 6 with remainder 0; or 24 = 6 × 4. Two factors 4 and 6.
        24 ÷ 5 = 4 with remainder 4; no factors.
        All factors greater that 5 already found, we stop the division process and write the list of factors 24 are 1, 2, 3, 4, 6, 8, 12 and 24.
    3. Solution
      We divide 120 by each of the numbers in the list. If the remainder is equal to zero the divisor (number in the list) is a factor of 120.
      120 ÷ 2 = 60 with remainder 0 , 2 is a factor of 120
      120 ÷ 5 = 24 with remainder 0 , 5 is a factor of 120
      120 ÷ 10 = 12 with remainder 0 , 10 is a factor of 120
      120 ÷ 11 = 10 with remainder 10 , 11 is NOT a factor of 120
      120 ÷ 20 = 6 with remainder 0 , 20 is a factor of 120
      120 ÷ 30 = 4 with remainder 0 , 30 is a factor of 120
      120 ÷ 50 = 2 with remainder 20 , 50 is NOT a factor of 120
      In the given list all are factors of 120 except 11 and 50.
    4. Solution
      We first find all factors of 12
      12 ÷ 1 = 12 with remainder 0 , 1 and 12 are factors of 12
      12 ÷ 2 = 6 with remainder 0 , 2 and 6 are factors of 12
      12 ÷ 3 = 4 with remainder 0 , 3 and 4 are factors of 12
      All factors greater that 3 already found, we stop the division process and write the list of factors of 12: 1, 2, 3, 4, 6 and 12.
      The factors of 24 were found in solution to 2) part d) and are given by
      1, 2, 3, 4, 6, 8, 12 and 24
      Common factors to 12 and 24 are: 1, 2, 3, 4, 6 and 12.
    5. Solution
      The first 5 mutliples mutliples of a number are obtained by multiplying that number by 1, 2, 3, 4 and 5
      1. The first 5 multiples of 2 are:
        2 × 1 = 2
        2 × 2 = 4
        2 × 3 = 6
        2 × 4 = 8
        2 × 5 = 10
      2. The first 5 multiples of 11 are:
        11 × 1 = 11
        11 × 2 = 22
        11 × 3 = 33
        11 × 4 = 44
        11 × 5 = 55
      3. The first 5 multiples of 25 are:
        25 × 1 = 25
        25 × 2 = 50
        25 × 3 = 75
        25 × 4 = 100
        25 × 5 = 125
    6. Solution
      The first 5 mutliples mutliples of 6 and 8 number are obtained by multiplying 6 and 8 by 1, 2, 3, 4 and 5
      1. The first 5 multiples of 6 are:
        6 × 1 = 6
        6 × 2 = 12
        6 × 3 = 18
        6 × 4 = 24
        6 × 5 = 30
      2. The first 5 multiples of 8 are:
        8 × 1 = 11
        8 × 2 = 16
        8 × 3 = 24
        8 × 4 = 32
        8 × 5 = 40                                         From : https://www.analyzemath.com/middle_school_math/grade_6/factors_multiples.html

Selasa, 30 Juni 2020

Examples of Mathematical Questions in English

Choose the correct answer!

1.Ming and Andrew made a cake and cut it into 8 equal pieces. They gave 3 pieces to Susan. What fraction of the cake is left?
a.7/8
b. 5/8
c.3/8
d.1/8



2. Steve checked out a book and a video from the local library. They were three days overdue when he returned them. The fine was 15 cents for each day the book was overdue, and 25 cents for each day the video was overdue. How much did Steve owe?
a.$0.40
b.$0.45
c.$0.75
d.$1.20

Sasha has a bag with
  • 5 grey balls,
  • 3 white balls, and
  • 4 striped balls.

3. If she takes a ball out of the bag without looking, what are her chances of getting a white ball?
a.1 chance out of 3
b.3 chances out of 9
c.3 chances out of 12
d.9 chances out of 12



4. Which of the following is equal to 104 X 50?
a.(100 X 5) + (4 X 5)
b.(100 X 5) + (4 X 50)
c.(100 X 50) + (4 X 50)
d.(100 X 50) + (40 X 50)



5.Admission to the Basketball Hall of Fame in Springfield is $5.00 per student. A group of students bought admission tickets. One student spent an extra $9.00 for a poster. The total amount they spent was $34.00. How many students were in the group?
a.4
b.5
c.6
d.7

Selasa, 24 Maret 2020

Tugas 3 Belajar di rumah Matematika 8 - STATISTIK


Klik Gambar & Simpan .. !
Selamat Mengerjakan





Nur Insa SPd - SMPN 6 Blora

Minggu, 22 Maret 2020

Sabtu, 21 Maret 2020